b^2-18b+91=5

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Solution for b^2-18b+91=5 equation:


Simplifying
b2 + -18b + 91 = 5

Reorder the terms:
91 + -18b + b2 = 5

Solving
91 + -18b + b2 = 5

Solving for variable 'b'.

Reorder the terms:
91 + -5 + -18b + b2 = 5 + -5

Combine like terms: 91 + -5 = 86
86 + -18b + b2 = 5 + -5

Combine like terms: 5 + -5 = 0
86 + -18b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-86' to each side of the equation.
86 + -18b + -86 + b2 = 0 + -86

Reorder the terms:
86 + -86 + -18b + b2 = 0 + -86

Combine like terms: 86 + -86 = 0
0 + -18b + b2 = 0 + -86
-18b + b2 = 0 + -86

Combine like terms: 0 + -86 = -86
-18b + b2 = -86

The b term is -18b.  Take half its coefficient (-9).
Square it (81) and add it to both sides.

Add '81' to each side of the equation.
-18b + 81 + b2 = -86 + 81

Reorder the terms:
81 + -18b + b2 = -86 + 81

Combine like terms: -86 + 81 = -5
81 + -18b + b2 = -5

Factor a perfect square on the left side:
(b + -9)(b + -9) = -5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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